Giải phương trình: cos^4x+sin^4(x+π/4)=1/4

Hướng dẫn giải:

Ta có: (*) \( \Leftrightarrow \frac{1}{4}{{(1+\cos 2x)}^{2}}+\frac{1}{4}{{\left[ 1-\cos \left( 2x+\frac{\pi }{2} \right) \right]}^{2}}=\frac{1}{4}\Leftrightarrow {{(1+\cos 2x)}^{2}}+{{(1+\sin 2x)}^{2}}=1 \)

 \( \Leftrightarrow 1+2\cos 2x+{{\cos }^{2}}2x+1+2\sin 2x+{{\sin }^{2}}2x=1\Leftrightarrow 2(\cos 2x+\sin 2x)=-2 \)

 \( \Leftrightarrow \cos 2x+\sin 2x=-1\Leftrightarrow \cos \left( 2x-\frac{\pi }{4} \right)=-\frac{1}{\sqrt{2}}=\cos \frac{3\pi }{4} \)

 \( \Leftrightarrow \left[ \begin{align}  & 2x-\frac{\pi }{4}=\frac{3\pi }{4}+k2\pi  \\  & 2x-\frac{\pi }{4}=-\frac{3\pi }{4}+k2\pi  \\ \end{align} \right. \) \( \Leftrightarrow \left[ \begin{align}  & x=\frac{\pi }{2}+k\pi  \\  & x=-\frac{\pi }{4}+k\pi  \\ \end{align} \right.,\text{ }k\in \mathbb{Z} \).